In the anhormonic vibrations, the situation more complex increases in vibrational energy increases the average bond length (rₐᵥ). The rotational constant varies even more vibrational energy. Since rₐᵥ increases with vibrational energy, B is smaller in the upper vibrational state than in the lower vibrational state. As an approximation of the value Bᵥ the rotational constant in the vibration level v is given by,
Bᵥ = Bₑ - α(v+1/2)..............(1)
Bₑ - equilibrium rotational constant α - a small positive constant.
Consider the fundamental vibrational change ie the change v = 0 →v = 1, and the respective B values B₀ and B₁. For this transition.
∆∈ = ∈ⱼ', v = 1 − ∈ⱼ", v =0 = ω̄₀ + B₁j' (j'+1) −
B₀ j" (j"+1) cm⁻¹ where ω₀ = ωₑ (1−2xₑ)
When then have two cases
(i) ∆J = +1, J' = J" + 1
∆∈ = v̄R = ω̄₀ + ( B₁ + B₀) ( J" + 1)² cm ⁻¹ ( J" = 0, 1,2,............)......... (2)
(ii) ∆J = −1, J' = J" + 1
∆∈ = v̄P = ω̄₀ + (B₁+B) (J' +1) + (B₁ + B₀)
(J' + 1)² cm⁻¹ (J' = 0,1,2.....)..........(3)
Where we have written vP and vR to represent the wave number respectively two equation can be determined as
V̄ P, R = ω̄₀ + ( B₁ + B₀) m (B₁ − B₂) m² cm⁻¹
( m = ±1, ±2, ±3...........)...........(4)
Where positive m values refer to the R branch negative to P branch lines. Since B₁ < B₂. The last terms, above equation is negative. It's effect on the spectrum of diatomic molecule is to crowd the rotational lines in the R branch lines more widely spaced as negative in increases.
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