i = Fkc e∝Fη/RT
Where 'c' refers to the concentration of species which supplies H⁺ to the cathodes.
The Overpotential for H₂ evolution is independent of the PH of the medium. This shows that H⁺ supplied by acid doesn't get deposited at the cathode even though [H ⁺] is higher in acid medium. Therefore it's suggested that H⁺ from weaker is getting deposited at the cathode. As the concentration of water will be in large excess. It's concentration will remain almost the same or "c" will be a constant at all PH. Hence ηH₂ remains to be the same.
The proton gets transferred from the OHP and it is an activation process. Only a portion or part of the emf or part of η is attributed to this proton transfer process.
The ∝ above in the equation is a fraction
0< 2< 1. To find out the value of ∝ . The following mechanism has been proposed.
From the water molecule present near the cathode H⁺ is transferred and to compensate for the loss, a proton migrates from neighbouring water molecules. After deposition of proton from the primary stealths protons from secondary stealths migrates. The OH⁻ formed interact or taken by the solvent. As the proton transfer occurs between two H₂O molecules, the transition state is highly symmetrical. Hence values of ∝ is assumed to be 0.5.
This theory is called Growths chain theory.
η = a+ 2.303 RT log i
∝F
∝ = 0.5 according to the above theory. Hence the slope of the straight line obtained from a graph of η vs log i should be 2.303 RT
∝F
and, so slope ≈ 0.118
Merits from this theory :-
(1) Using symmetric transition state involving proton proton transfer between two H₂O molecules, the value of ∝ is given as 0.5 molecules, the value of ∝ is given as 0.5 and the slope called for η vs log i graph is 0.118 which agree with experimental value for most of the metals except platinised Pt.
(2) This theory brings out the iii rity in the mechanism of ηH₂ and ɳO₂
(3) Nature of the electrode :-
Metals which from stronger M⁺ - H bond will pull the H⁺ readily from H₂O. Hence H⁺ transfer, will be faster on these metals (e.g) Pt.
Over metals forming stronger M-H bonds, catalytic action is slow step and they will have lower ηH₂.
Metals (Hg) which form weak M- H bonds will repel H⁺ from water or H⁺ transfer from H₂O over Hg will be very slow.
Over metals forming weak M-H bond, the proton transfer is the slow step and they will have higher ηH₂.
No comments:
Post a Comment
Thanks for reading